(相关资料图)

继续欢迎批评指正建议 ^^

曾经的活动是购买订单返流量（日志在 flow_rebate_log），后来改成返佣金（日志在 money_rebate_log）。现在需要 按照用户返佣金额排名，如果不存在金额，则按 返流量 排名。其他需要列出的字段：username(用户名 连接 users表获得)，用户返佣金额，用户返佣金的订单数，用户返流量数，用户返流量的订单数

SELECT r.*,u.username,       flow_order_num + money_order_num as order_num,flow_order_money + money_order_money as order_moneyfrom        (            (SELECT f.uid,rebate_flow,flow_order_num,rebate_money,money_order_num,f.money as flow_order_money,m.money as money_order_moneyfrom(SELECT sum(rebate_value) as rebate_flow,count(*) as flow_order_num,uid,money FROM `flow_rebate_log` group by uid) fleft join(SELECT sum(consume_money) as rebate_money,count(*) as money_order_num,uid,money FROM `money_rebate_log` group by uid) m on m.uid = f.uid)union(SELECT m.uid,rebate_flow,flow_order_num,rebate_money,money_order_num,f.money as flow_order_money,m.money as money_order_moneyfrom(SELECT sum(rebate_value) as rebate_flow,count(*) as flow_order_num,uid,money FROM `flow_rebate_log`  group by uid ) f  right join(SELECT sum(consume_money) as rebate_money,count(*) as money_order_num,uid,money FROM `money_rebate_log`  group by uid) m on m.uid = f.uid)        ) rleft join `users` uon u.id = r.uid

排序在php代码里，因为想利用 TP框架的分页功能返回给前端。

//$tb = "sql语句"; $list = Db::table("($tb) t")        ->order("rebate_money desc,rebate_value desc")        ->limit(50)        ->select();

因为有的用户 只出现在 flow_rebate_log,有的只出现在 money_rebate_log, 需要一个全连接。使得每条记录 同时 包含用户的返流量和返金额信息。 而mysql不支持full join，只能用一个trick ： m (money_rebate_log) full join f(flow_rebate_log) 相当于

m left join funionm right join f

由于 f.uid 和 m.uid 连接后 可能会有一个值是空的，那我们要取 肯定有值的。所以先选取 有效列 再 union。值得注意的是 union 和 union all 是有一点区别的，union 是去重的，union all是全部保留的。这里 每个用户只对应一条记录。所以 union 就可以了。

模拟“full join” 和 union

标签：